Good day, Consider the following makefile:
foo : bar.o
bar.o : bar.cpp
g++ -c -o $@ $<
Here I don't have a command for 'foo'. 'foo' is not declared
phony. However make 'imagines' that this target is somehow
gets updated. Obviously there is no way 'foo' can be created
(side-effects aside for a moment) so effectively 'foo' becomes
an implicit phony target. My question is when this logic can be
useful?
thanks,
-boris
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