%% richard t <[EMAIL PROTECTED]> writes:
rt> here is an example showing multiple targets...
rt> x.class y.class z.class : x.java y.java z.java
rt> javac -g $<
rt> I guess I understood that the "$<" would match each
rt> source file that needed to be compiled?
No. It matches the FIRST source file in each target's list of
prerequisites. What you have written above is really shorthand for
writing three separate rules:
x.class : x.java y.java z.java
javac -g $<
y.class : x.java y.java z.java
javac -g $<
z.class : x.java y.java z.java
javac -g $<
Note how each target has the SAME list of prerequisites.
So, in all cases $< will be the first one, which is always x.java.
rt> now on to the other part that you mentioned... the
rt> "$^" macro, so based on the make line toward the top
rt> of this e-mail, it would match?:
rt> "$^" = x.java y.java z.java
rt> so this would produce the following command?:
rt> javac -g x.java y.java z.java
Yes.
rt> I would also assume that I could use the "subst" to
rt> create the package names for each source file?
rt> (that would be quite useful...)
Do not use "subst". "subst" changes EVERY instance of the string
anywhere; this can lead to errors if you have multiple instances of the
same string in a single word.
Use patsubst instead; it's much safer.
--
-------------------------------------------------------------------------------
Paul D. Smith <[EMAIL PROTECTED]> Find some GNU make tips at:
http://www.gnu.org http://make.paulandlesley.org
"Please remain calm...I may be mad, but I am a professional." --Mad Scientist
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