This was a very shortened version. the defines are necessary as well as
the evals.
But I got it to work with the subst instead of the patsubst
  Thanks for your response.

> -----Original Message-----
> From: John Graham-Cumming [mailto:[EMAIL PROTECTED] On 
> Behalf Of John Graham-Cumming
> Sent: Tuesday, May 23, 2006 9:04 AM
> To: PATTON, BILLY (SBCSI)
> Cc: [email protected]
> Subject: Re: problems with $$
> 
> 
> PATTON, BILLY (SBCSI) wrote:
> > I have the following example :
> > INCLUDE := -Idogs -Ipigs -Isheep -Irats
> > 
> > PC_TO_O = @echo $$(INCLUDE:-I=include\=)
> > 
> > .PHONY : x
> > 
> > define x
> > x : ; $(PC_TO_O)
> > endef
> > $(eval $(call x))
> > 
> > It need to print out
> > include=dogs include=pigs include=sheep include=rats
> 
> 1. A substitution reference $(X:A=B) change A to B for each A _at the 
> end_ of a word in $(X).  Hence your substitution reference 
> doesn't work. 
>   If you fix that your example will work.
> 
>      PC_TO_O = @echo $$(patsubst -I%,include=%,$(INCLUDE))
> 
> 2. I don't think you need $(eval $(call x)) at all.  Try doing
> 
>      INCLUDE := -Idogs -Ipigs -Isheep -Irats
> 
>      PC_TO_O = @echo $(patsubst -I%,include=%,$(INCLUDE))
> 
>      .PHONY : x
> 
>      define x
>      x : ; $(PC_TO_O)
>      endef
> 
>      $(x)
> 
> 3. Since you only have one line in your rule for x you don't 
> need define
> 
>      INCLUDE := -Idogs -Ipigs -Isheep -Irats
> 
>      PC_TO_O = @echo $(patsubst -I%,include=%,$(INCLUDE))
> 
>      .PHONY : x
>      x = x : ; $(PC_TO_O)
>      $(x)
> 
> John.
> -- 
> John Graham-Cumming
> [EMAIL PROTECTED]
> 
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