I just upgraded from v3.80 to 3.81 because of strange bugs when using
$(eval ...) on a MacOsX os (the same makefile works fine with a 3.80
make on Linux).
But now, I am "completelly lost" with the "new" behavior of $(eval ..);
to make things work, I have to sometimes use not just TWO $'s but FOUR
of them.
Is there some "expert" to explain this ?, or point to a good and
uptodate (3.81) tutorial for the $(eval ...) function ?.
Here is a makefile example showing the behaviour:
# -*- Makefile -*-
$(warning MAKE_VERSION=$(MAKE_VERSION))
x := x_val
$(eval $(warning 1 dollar: x=$x))
$(eval $(warning 2 dollars: x=$$x))
$(warning looks good, with 1 and 2 dollars)
%todo := 2dollars 4dollars
.PHONY: $(%todo)
todo: $(%todo)
$(eval 2dollars: \; @echo with 2 dollars: target=$$@)
$(eval 4dollars: \; @echo with 4 dollars: target=$$$$@)
And is here what I get:
../src/makefile.eval:3: MAKE_VERSION=3.80
../src/makefile.eval:6: 1 dollar: x=x_val
../src/makefile.eval:7: 2 dollars: x=$x
../src/makefile.eval:8: looks good, with 1 and 2 dollars
with 2 dollars: target=2dollars
with 4 dollars: target=
and
../src/makefile.eval:3: MAKE_VERSION=3.81
../src/makefile.eval:6: 1 dollar: x=x_val
../src/makefile.eval:7: 2 dollars: x=$x
../src/makefile.eval:8: looks good, with 1 and 2 dollars
with 2 dollars: target=
with 4 dollars: target=4dollars
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