On Wed, 2010-06-09 at 17:25 -0500, Peng Yu wrote:
> No. It doesn't work.
> $ make
> echo ./ *.txt/
> ./ x.txt/
> $ cat Makefile
> .PHONY: all
>
> all:
> echo $(dir (wildcard *.txt/.))
If someone tells you something works and it doesn't work for you, please
double- and triple-check your work before responding. In programming
every single character counts.
Here, you've forgotten the "$" before the wildcard function.
Here's what I get:
~$ mkdir tst
~$ cd tst
tst$ touch foo.txt
tst$ mkdir bar.txt
tst$ mkdir baz.txt
tst$ touch blah.txt
tst$ echo 'x: ; @echo "$(wildcard *.txt/.)"' | make -f-
bar.txt/. baz.txt/.
Which appears to me to be what you were looking for. Adding $(dir ...)
will strip off the "." but not the trailing slash (I forgot this is how
$(dir ...) is documented to work). If you want to remove both you can
use patsubst:
tst$ echo 'x: ; @echo "$(dir $(wildcard *.txt/.))"' | make -f-
bar.txt/ baz.txt/
tst$ echo 'x: ; @echo "$(patsubst %/.,%,$(wildcard *.txt/.))"' | make
-f-
bar.txt baz.txt
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