Sébastien Hinderer (2017/07/26 15:18 +0200): > Oh great! I was not aware of this. > > So am I correctin assuming that something like > > parsers := foo.mly bar.mly baz.mly > > $(parsers): %.ml %.mli > ocamlyacc $< > > would work the expected way?
Sorry, I meant:
parsers := foo.mly bar.mly baz.mly
$(parsers): %.ml %.mli: %.mly
ocamlyacc $<
Sébastien.
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