I think we only want to consider the roof when looking at standing room.
I looked at "average human height" in wikipedia, and the
not-entirely-unreasonable figures give us 5-6 feet depending on, well, I
suppose a mix of ancestors and food etc. (And age and male-femaleity, of
course.)
The walls start at 4 feet and the highest point is 8 feet, so standing room
is not the full hexagon floor, but a smaller hexagon at the height of the
(adult) heads.

I looked at this visually for the H13
http://www.appropedia.org/Hexayurt_H13and even for the H14 (never
built yet, AFAIK), and standing room is
substantially larger, like 66% more, cos you start with 6 small triangles
and H13 adds 4 more such triangles (if you look at that page), for a single
extra panel (even more for the H14).

I haven't been able to figure out how to make an H13 out of plywood, tho'.
you know, with 120º and 150º blocks and all that. Just a minor challenge
here, I'm sure. <grin>
http://www.appropedia.org/Hexayurt_Plywood (much of the documentation is at
the Discussion subpage, cos I don't feel confident enough that I understand
how it works yet).

Lucas

2011/6/18 Steve Upstill <[email protected]>

> Or, forget the roof: the walls form a hexagon 8' on a side. A hexagon is
> six equilateral triangles, each 8' on a side. The height of an equilateral
> triangle is sqrt(8*8-4*4) = 6.92, so its area is 6.92*8/2 = 27.7. Six such
> triangles will thus be 166.28 square feet. Good job, Vinay!
>
> Just looking at it another way...
>
> Cheers,
> Steve Upstill
> --
> Injustice is relatively easy to bear; what stings is justice.
> -- H. L. Mencken
>
>
> On Jun 17, 2011, at 12:32 PM, Bill Wiltschko wrote:
>
> 166 is based on the known dimensions and angle of the roof.  The roof
> consists of half sections of 4x8 foot panels set at a 30 degree angle from
> horizontal.  So, the 8ft long roof triangles trace a distance of 8 times
> cos(30) along the ground, or 6.93 ft.  Each wall is 8 ft wide, so the area
> of the triangle made by a wall’s intersection with the ground and the center
> point of the hexayurt is 8 times 6.93 divided by 2 (base times height
> divided by 2).  Multiple by 6 to get the total area of the hexayurt.****
> ** **
> Bill****
> ** **
> *From:* [email protected] [mailto:[email protected]] *On
> Behalf Of *ken winston caine
> *Sent:* Friday, June 17, 2011 11:02 AM
> *To:* [email protected]
> *Subject:* Re: [hexayurt] Legal Status for Hexayurt Constructions ? -
> Construction Permit Required ?****
> ** **
> How can that be?****
>  ****
> Please work out the math for us in a message so we can see it.****
>  ****
> If you just had an 8-footx8-foot floor area you would have 64 square feet.
> And with the hexagon made up of SIX (not five) 8-foot walls, you have
> substantially more than an 8-footx8-foot floor area.****
>  ****
> Am sure I must have missed an earlier message in this thread, but the
> square-footage number leaped out at me in this message. For year's I've
> accepted Vinay's calculation that the traditional hexayurt provides 166
> square feet of floor area. I'm pretty sure he's calculated that correctly.
> But I'm not a math whiz and need to see how you are working out these
> numbers, if you don't mind.****
>  ****
> Thanks,****
> ken****
> ----- Original Message -----****
> *From:* Ray Kornele <[email protected]>****
> *To:* [email protected]****
> *Sent:* Friday, June 17, 2011 11:41 AM****
> *Subject:* Re: [hexayurt] Legal Status for Hexayurt Constructions ? -
> Construction Permit Required ?****
> ** **
>
> If you do the math you may find that is not the case.
> It actually figures out to 41.56928 square feet for the one mane of 5
> sheets of plywood. Where the 166 figure came from, but it's WAY off.
>
>
> KrazyKyngeKorny (Krazy, not stupid)
>
> ****
> On Fri, Jun 17, 2011 at 9:19 AM, Bill Wiltschko <[email protected]>
> wrote:****
> The typical hexayurt is 166 sq ft.****
>  ****
> Bill****
> ** **
> ** **
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