Performance is ALWAYS an issue. 

But am I correct in assuming that the performance increase would be
approximately inversely proportional to the number of shards queried? 

My point is that the amount of work required to implement this should be
worth what we think the expected gain will be.

John G.
http://thediningphilosopher.blogspot.com

 
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Today's Topics:

   1. HSearch: Using sharding and avoiding query on     multiple shards
      (Emmanuel Bernard)
   2. Re: HSearch: Using sharding and avoiding query on multiple
      shards (Sanne Grinovero)


----------------------------------------------------------------------

Message: 1
Date: Wed, 30 Jul 2008 20:36:13 -0400
From: Emmanuel Bernard <[EMAIL PROTECTED]>
Subject: [hibernate-dev] HSearch: Using sharding and avoiding query on
        multiple shards
To: hibernate-dev@lists.jboss.org, Aaron Walker
        <[EMAIL PROTECTED]>
Message-ID: <[EMAIL PROTECTED]>
Content-Type: text/plain; charset="us-ascii"

Today, in Hibernate Search, a query is applied on all shards. We use a  
MultiReader to wrap them together.
In some sharding scenario, it makes sense to apply the query on a  
single shard or a subset of the shards.

We could add the following API to IndexShardingStrategy

public DirectoryProvider<?>[]  
getDirectoryProvidersForQuery(o.a.l.search.Query query);

The query could be analyzed by the sharding strategy to detect boolean  
queries on their sharding criteria

//query building
BooleanQuery bQuery = new BooleanQuery();
bQuery.add(regularQuery, Occur.MUST);
bQuery.add( new TermQuery( new Term("distributor.id", "2"),  
Occur.MUST ); //only occurs in shard 1

public DirectoryProvider<?>[]  
getDirectoryProvidersForQuery(o.a.l.search.Query query) {
   if (query instanceof BooleanQuery) {
     List<BooleanClause> clauses =  
BooleanQuery.class.cast(query).clauses
   }
   int restrictedShard;
   boolean isAllMust = true;
   for (BooleanClause clause : clauses) {
     if (clause.getOccur() != Occur.MUST) { isAllMust = false; break; }
     if ( clause.getQuery() instanceof TermQuery ) {
       Term term = TermQuery.class.cast( clause.getQuery() ).getTerm();
       if (term.field().equals("distributor.id")) { restrictedShard =  
Integer.parse(term.text(); }
     }
   }
   if (isAllMust && restrictedShard != null) return new Provider[]  
{ providers[restrictedShard-1] };
   else return providers;
}


That's very flexibile but quite hard to implement correctly especially  
since the query tree structure might not be trivial

The alternative strategy is to have the following API on  
IndexShardingStrategy

public DirectoryProvider<?>[] getDirectoryProvidersForQuery(Object  
hint);

and a corresponding fullTextQuery.setShardHint(Object);

A query could "know it targets shard 2 and pass the information to the  
strategy through a standard language:

fullTextQuery.setShardHint("Sony");

public DirectoryProvider<?>[] getDirectoryProvidersForQuery(Object  
hint) {
   if (String.class.isInstance(hint) &&  
String.class.cast(hint).equals("Sony")) {
     return new Provider[] { providers[2] }
   }
   else {
     return providers;
   }
}

WDYT? How useful would that be?
--
Emmanuel Bernard
http://in.relation.to/Bloggers/Emmanuel | http://blog.emmanuelbernard.com 
  | http://twitter.com/emmanuelbernard
Hibernate Search in Action (http://is.gd/Dl1)

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------------------------------

Message: 2
Date: Thu, 31 Jul 2008 15:22:52 +0200
From: "Sanne Grinovero" <[EMAIL PROTECTED]>
Subject: Re: [hibernate-dev] HSearch: Using sharding and avoiding
        query on        multiple shards
To: "Emmanuel Bernard" <[EMAIL PROTECTED]>
Cc: hibernate-dev@lists.jboss.org, Aaron Walker
        <[EMAIL PROTECTED]>
Message-ID:
        <[EMAIL PROTECTED]>
Content-Type: text/plain; charset=UTF-8

Hello,
the feature is awesome and I know of several real world cases were it
would have been
both useful and would have performed better.

about the API, wouldn't it make more sense to have it look like a filter?

regards,
Sanne

2008/7/31 Emmanuel Bernard <[EMAIL PROTECTED]>:
> Today, in Hibernate Search, a query is applied on all shards. We use a
> MultiReader to wrap them together.
> In some sharding scenario, it makes sense to apply the query on a single
> shard or a subset of the shards.
> We could add the following API to IndexShardingStrategy
> public
> DirectoryProvider<?>[] getDirectoryProvidersForQuery(o.a.l.search.Query
> query);
> The query could be analyzed by the sharding strategy to detect boolean
> queries on their sharding criteria
> //query building
> BooleanQuery bQuery = new BooleanQuery();
> bQuery.add(regularQuery, Occur.MUST);
> bQuery.add( new TermQuery( new Term("distributor.id", "2"), Occur.MUST );
> //only occurs in shard 1
> public
> DirectoryProvider<?>[] getDirectoryProvidersForQuery(o.a.l.search.Query
> query) {
>   if (query instanceof BooleanQuery) {
>     List<BooleanClause> clauses = BooleanQuery.class.cast(query).clauses
>   }
>   int restrictedShard;
>   boolean isAllMust = true;
>   for (BooleanClause clause : clauses) {
>     if (clause.getOccur() != Occur.MUST) { isAllMust = false; break; }
>     if ( clause.getQuery() instanceof TermQuery ) {
>       Term term = TermQuery.class.cast( clause.getQuery() ).getTerm();
>       if (term.field().equals("distributor.id")) { restrictedShard =
> Integer.parse(term.text(); }
>     }
>   }
>   if (isAllMust && restrictedShard != null) return new Provider[] {
> providers[restrictedShard-1] };
>   else return providers;
> }
>
> That's very flexibile but quite hard to implement correctly especially
since
> the query tree structure might not be trivial
> The alternative strategy is to have the following API on
> IndexShardingStrategy
> public DirectoryProvider<?>[] getDirectoryProvidersForQuery(Object hint);
> and a corresponding fullTextQuery.setShardHint(Object);
> A query could "know it targets shard 2 and pass the information to the
> strategy through a standard language:
> fullTextQuery.setShardHint("Sony");
> public DirectoryProvider<?>[] getDirectoryProvidersForQuery(Object hint) {
>   if (String.class.isInstance(hint) &&
> String.class.cast(hint).equals("Sony")) {
>     return new Provider[] { providers[2] }
>   }
>   else {
>     return providers;
>   }
> }
> WDYT? How useful would that be?
> --
> Emmanuel Bernard
> http://in.relation.to/Bloggers/Emmanuel | http://blog.emmanuelbernard.com
| http://twitter.com/emmanuelbernard
> Hibernate Search in Action (http://is.gd/Dl1)
>
> _______________________________________________
> hibernate-dev mailing list
> hibernate-dev@lists.jboss.org
> https://lists.jboss.org/mailman/listinfo/hibernate-dev
>
>


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