EMF + Metamodel are standard JPA contracts:
````
try {
emf.getMetamodel().managedType( theClass );
}
catch ( IllegalArgumentException e ) {
// JPA defined exception if the passed class is not a managed type
}
````
Again, that will (should) work on any provider
On Thu, Apr 25, 2019 at 1:01 PM Guillaume Smet <guillaume.s...@gmail.com>
wrote:
> Hi,
>
> In Hibernate Validator, we have a TraversableResolver which avoids to
> validate the uninitialized properties of an entity.
>
> This is done in
>
> https://github.com/hibernate/hibernate-validator/blob/master/engine/src/main/java/org/hibernate/validator/internal/engine/resolver/JPATraversableResolver.java#L35
> and, as you can see, we execute Persistence.getPersistenceUtil().isLoaded(
> traversableObject, traversableProperty.getName() ) even if the
> traversableObject has nothing to do with Hibernate ORM.
>
> I'm looking for an API that could tell me if an object is a class
> potentially managed by ORM (be it an entity, an embeddable or whatever: any
> class potentially containing a lazy field).
>
> I was thinking that maybe injecting an EntityManagerFactory (it would
> require CDI though) and using the Metamodel could somehow work... but the
> PersistenceUtil API we currently use is capable of dealing with several
> persistence providers and I don't think the injected EntityManagerFactory
> approach will fly in this case.
>
> Is there something I could use to do that, that would be portable and cover
> the cases currently (somehow) taken care of?
>
> Any ideas welcome.
>
> Thanks!
>
> --
> Guillaume
> _______________________________________________
> hibernate-dev mailing list
> hibernate-dev@lists.jboss.org
> https://lists.jboss.org/mailman/listinfo/hibernate-dev
>
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