--- [EMAIL PROTECTED] wrote:
>
> You need to learn about the mysteries of the
> unsaved-value
> attribute :)
>
> Hibernate looks at the id value to determine if an
> object
> discovered by cascade is "new" or not. So, if you
> have an
> object with a Long identifier, set
> unsaved-value="null".
I noticed that you use "Long" class as identified. Can
I use primitive type long as identifier and use "0" as
unsaved-value?
> Note that another approach is to save() the Item
> explicitly,
> before flushing.
>
>
>
>
>
>
>
> "Matt Dowell"
>
>
> <[EMAIL PROTECTED]>
> To:
> <[EMAIL PROTECTED]>
>
> Sent by:
> cc:
>
>
> [EMAIL PROTECTED] Subject:
> [Hibernate] Saving collections...
>
> eforge.net
>
>
>
>
>
>
>
>
> 30/01/03 09:56 AM
>
>
>
>
>
>
>
>
>
>
>
>
> Easy question, I think.
>
> I am trying something like this:
>
> Product p = new Product();
> p.setName("blah");
>
> ProductLineItem item = new ProductLineItem();
> item.setName("blah line item");
>
>
> // Add a line item to the product
> p.addLineItem(item);
>
>
> Session.save(p);
>
>
> ....and it is inserting the Product, and trying to
> update the LineItem.
> Can it insert the product, then insert the LineItem
> or is this not
> supported?
>
> Thanks,
>
> Matt Dowell
> Notiva Corp.
>
>
>
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