> > concat(?1 || ?2) is parsed not as one argument but three, 
> since there 
> > are three tokens, i.e. ?1, || and ?2.
> 
> oh - afraid of sounding stupid, but shouldn't that be parsed as a
> functioncall(expression) ?
> where expression is (x op y) in this case ?

Yes, sorry, of course, it is parsed like this.
I had a bug in creating an argument list. It works now.

Thanks.


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