Hi There, I am trying to convert HL7 - XML message to HL7 - ER7 format. However after conversion all whitespace are getting trimed off, which is part of the original XML message. In source code below, PipeParser.encode(ER7Msg) is the one who is triming all whitespaces. Is there a way I can still retain all whitespace in encodedMessage?
XMLParser parseXML = new DefaultXMLParser(); parseXML.setValidationContext(new NoValidation()); PipeParser pipeParser = new PipeParser(); pipeParser.setValidationContext(new NoValidation()); Message ER7Msg = parseXML.parse(XMLString); ER7Msg.setValidationContext(new NoValidation()); encodedMessage = pipeParser.encode(ER7Msg ); -- View this message in context: http://www.nabble.com/XML-to-ER7-conversion-using-pipeParser.encode-tp23399607p23399607.html Sent from the hl7api-devel mailing list archive at Nabble.com. ------------------------------------------------------------------------------ The NEW KODAK i700 Series Scanners deliver under ANY circumstances! Your production scanning environment may not be a perfect world - but thanks to Kodak, there's a perfect scanner to get the job done! With the NEW KODAK i700 Series Scanner you'll get full speed at 300 dpi even with all image processing features enabled. http://p.sf.net/sfu/kodak-com _______________________________________________ Hl7api-devel mailing list Hl7api-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/hl7api-devel