Vyacheslav - try:
char szMes[25]; void ReturnTestString(char* szSring, int Id); ReturnTestString(szMes, 1); the '&' sign before a variable name means "address-of the variable." when declaring the function, the name szString is just the name of the variable inside the function. ReturnTestString just needs to know the variable is a string, which is char*. btw, putting a * after a type (like char*) means the variable is a pointer to that type. for more info, check out: http://www.cplusplus.com/doc/tutorial/tut3-2.html (about strings) http://www.cplusplus.com/doc/tutorial/tut3-3.html (about pointers) hope this helps, barret ----- Original Message ----- From: "Vyacheslav Djura" <[EMAIL PROTECTED]> To: "barret" <[EMAIL PROTECTED]> Sent: Saturday, October 05, 2002 3:18 PM Subject: Re[2]: [hlcoders] returning string > Hello barret, > > Saturday, October 5, 2002, 3:56:48 PM, you wrote: > > b> hi - > > b> i did something similar, but i used: > > b> char szMes[25]; //need szMes to be a string, not a char. in this case an > b> array of chars. > b> //25 is just my guess for how big it can get > Then, how to write header of this function (char* &szSring,int Id) so > array will be fixed (25) ? > I am not good at C++'s "*" > and "&"? > > thanks... > > -- > Best regards, > Vyacheslav mailto:[EMAIL PROTECTED] > > _______________________________________________ > To unsubscribe, edit your list preferences, or view the list archives, please visit: > http://list.valvesoftware.com/mailman/listinfo/hlcoders > > _______________________________________________ To unsubscribe, edit your list preferences, or view the list archives, please visit: http://list.valvesoftware.com/mailman/listinfo/hlcoders
