Bill,

On 29 Jul 2012, at 07:28, Bill Richter wrote:

>   https://dl.dropbox.com/u/34693999/nonobv.pdf
> 
> Rob, I like your 2nd proof (although I think your 4 cases are about P and not 
> P, instead of P and Q),

My argument does work exactly as stated, but I agree that it is simpler to 
avoid having overlapping cases by doing the case analysis as you suggest. 
Thanks for the improvement, which I have adopted in the write-up.

> and it got me thinking, and I now have some understanding of Los's Logic 
> problem.  The problem with Los's result is it makes no sense: P is symmetric 
> and transitive, Q is transitive, P or Q is true, show either all P or all Q.  
> Our reaction is What is going on???  That's why it's so impressive you solved 
> it.  But I made some progress understanding it:
> 
> The result is almost about entirely about P, with Q almost being ~P.  So 
> let's prove the case  special case Q = ~P first.  That turns out to have a 
> comprehensible proof!  Then we just have to fiddle with the proof a bit to 
> handle the general case.  Below is my miz3 proof of Los's Logic result, to a 
> large extent a modification of your 2nd proof.

I am not quite sure exactly what you were trying to achieve here. I would have 
hoped that miz3 would be able to express my 2nd proof as it stands. Not knowing 
miz3, I have done the next best things with the tools I do know and done a 
ProofPower transcription of my 2nd proof with your improvement in a 
"quasi-declarative" style. See:

https://dl.dropbox.com/u/34693999/los-non-obv-proof.pdf

I am guessing that you didn't really want to express my 2nd proof as is, but 
were after a comprehensible proof expressed in miz3. I think one needs to have 
a comprehensible proof in mind to achieve that and I don't quite see one 
following  your approach. My proof 1 at least has a comprehensible proof 
strategy, and that may be the best you can hope for. Did you not find proof 1 
comprehensible?

Regards,

Rob.


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