Did you figure this problem out? It looks like there aren't any
experts on using the integral theories on this list at the moment,
unfortunately...

On Sun, Dec 15, 2013 at 8:28 AM, 赵刚 <yefengl...@gmail.com> wrote:
> Thank you for your reply!I want to prove this
> g`! f:real->real a:real !b:real. &0 <= a /\ &0 <= b /\ integrable (&0,b) f
> ==> (integral(&0,a)(\y. integral(&0,y)(\x.f x * y ) ) = integral(&0,a)(\y.
> integral(&0,y)(\x.f x)* y ))`;
> the problem is this proof needs condition "&0 <= y", but I can't proof it
> from "\y".
> can you help me prove it ? Thank you very much!
>
>
> 2013/12/14 Ramana Kumar <ram...@member.fsf.org>
>>
>> I'm not sure I understand what the problem is. Perhaps you could show
>> us something that you want to prove but cannot prove?
>> The term you showed looks fine to me for a double integral.
>> It doesn't matter if "x" in  "(\x. f x * y) : real -> real" is
>> unbounded, because "integral (a,b)" puts the bounds on.
>>
>> On Mon, Dec 9, 2013 at 10:28 AM, 赵刚 <yefengl...@gmail.com> wrote:
>> > I just want to define a Double integral like "integral (c,d)(\y.
>> > integral(a,b)(\x. f x * y))"
>> > this define just can do on HOL4, but can't compute the internal
>> > integral,because the \x. belong to from negative infinity to positive
>> > infinity,but the variable of internal integral just belong to (a,b). So
>> > it's
>> > not equal,someone can help me ~very thanks!
>> >
>> >
>> >
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>
>
>
>
> --
> 赵刚

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