can I do $value = shift ||= "Default value"
?
On Tue, Jul 22, 2008 at 9:36 AM, Robert Boone <[EMAIL PROTECTED]> wrote:
>
> The short cut for if(!defined $value); is a perl 5.10/6 feature:
> $value //= "some sorta default";
>
> The other is good in all perl 5 version and lower, I think:
> $value = "some sorta default" if(!$value);
> becomes
> $value ||= "some sorta default";
>
>
> On Jul 22, 2008, at 9:31 AM, Todd Rinaldo wrote:
>
>> ok so someone explain these operators, cause obviously I shoulda read
>> the whole camel book!
>>
>> Here is what I've always had to do the hard way. what's the simpler?
>>
>> I often do this
>> sub foo {
>> my $value = shift;
>> $value = "some sorta default" if(!defined $value);
>>
>> }
>>
>> Of course sometimes I want to do the permutation:
>>
>> sub bar {
>> my $value = shift;
>> $value = "some sorta default" if(!$value);
>>
>> }
>>
>> is there a simpler way?
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>
>
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>
--
Todd Rinaldo
[EMAIL PROTECTED]
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