Hello Steve, you can implement a PartSource that returns 0 as the content length, an empty string as the file name, and ByteArrayInputStream(new byte[0]) as the InputStream.
And yes, it does make sense. hope that helps, Roland [EMAIL PROTECTED] 06.03.2005 22:09 Please respond to "HttpClient User Discussion" To [email protected] cc Subject how do u simulate sending a blank file field with httpclient? Ive been trying to figure out how to send a blank file field with httpclient. Ive managed to work out how to use the multipartform encoded http post and can send a file ok, but what i would like to do is to be able to post a filepart but not actually send a file, which would simulate a person submitting a form that includes a file field, but they havent actually chosen a file to submit. i hope that makes sense? the actual http headers that are submitted when no file is selected and the form is submitted looks something like this: ---------- Content-Disposition: form-data; name="SomeFile"; filename="" Content-Type: application/octet-stream ----------- i have tried things like creating a null file for the filepart or making the filename "", but both these methods caused an exception to be thrown. does anyone know the correct way of doing this? cheers, steve --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
