On 22/02/06, Sanjeev Kumar Neemkar <[EMAIL PROTECTED]> wrote: > Hello Roland, > > Considering URL-1 as http://www.apache.org/ and URL-2 as > http://www.apache.org/foundation/faq.html, below is the piece of code. > As per the steps and advice, which i followed as said, but it is again > giving ResponseBody for URL-2 as the that of URL-1. > Am i missing something, please correct me. > > Requirement: URL-2 is embeded in the page of URL-1. I need to simulate > the hyper-link(URL-2) clicking in the page of URL-1 using HTTPClient. > > Please help, > > Thanks in Advance, > Sanjeev Kumar Neemkar > > Java Code used as below: > ****************************** > > import java.io.IOException; > > import org.apache.commons.httpclient.DefaultHttpMethodRetryHandler; > import org.apache.commons.httpclient.HttpClient; > import org.apache.commons.httpclient.HttpException; > import org.apache.commons.httpclient.HttpStatus; > import org.apache.commons.httpclient.methods.GetMethod; > import org.apache.commons.httpclient.params.HttpMethodParams; > > public class HttpClientTutorial { > > private static String url = "http://www.apache.org/";; > > public static void main(String[] args) { > // Create an instance of HttpClient. > HttpClient client = new HttpClient(); > > // Create a method instance. > GetMethod method1 = new GetMethod(url); //URL-1 > //http://www.apache.org/foundation/faq.html > GetMethod method2 = new GetMethod(url + "foundation/faq.html"); //URL-2 > > // Provide custom retry handler is necessary > method1.getParams().setParameter(HttpMethodParams.RETRY_HANDLER, > new DefaultHttpMethodRetryHandler(3, false)); > // Provide custom retry handler is necessary > method2.getParams().setParameter(HttpMethodParams.RETRY_HANDLER, > new DefaultHttpMethodRetryHandler(3, false)); > > try { > // Execute the method. > int statusCode = client.executeMethod(method1); > > if (statusCode != HttpStatus.SC_OK) { > System.err.println("Method1 failed: " + method1.getStatusLine()); > } > > // Read the response body. > byte[] responseBody1 = method1.getResponseBody(); > //Release the connection. > method1.releaseConnection(); > // Deal with the response. > // Use caution: ensure correct character encoding and is not binary > // data > System.out.println("URL-1::" + new String(responseBody1)); > > ////////////////////URL-2///////////////////// > // Execute the method. > int statusCode2 = client.executeMethod(method2); > > if (statusCode2 != HttpStatus.SC_OK) { > System.err.println("Method2 failed: " + method2.getStatusLine()); > } > > // Read the response body. > byte[] responseBody2 = method1.getResponseBody(); ^^^^^^^^^^^ > //Release the connection. > method2.releaseConnection(); > // Deal with the response. > // Use caution: ensure correct character encoding and is not binary > // data > System.out.println("URL-2::" + new String(responseBody2)); > > } catch (HttpException e) { > System.err.println("Fatal protocol violation: " + e.getMessage()); > e.printStackTrace(); > } catch (IOException e) { > System.err.println("Fatal transport error: " + e.getMessage()); > e.printStackTrace(); > } finally { > // Release the connection. > //method1.releaseConnection(); > } > } > } > > ....................................................................................................................................................................................................... > On 2/21/06, Roland Weber <[EMAIL PROTECTED]> wrote: > > > > Hello Sanjeev, > > > > > My requirement is, to follow the hyper-link present in the response html > > > (Welcome/Home Page). I mean i want to click on test-hyper-link and get > > the > > > response. > > > > > > Is there any way to do this ? > > > > You've got the page. Scan it for the hyperlink to get the new URL. > > > > > Link URL on Welcome Page: > > > > > https://abcdev.test.com/ABCProject/servlet/PageDirector?choice=upload&userRole=ABCUser > > > > That link looks so static you can probably hard-wire it into your > > application. > > > > > It can be Get Method or Post Method in real scenario. > > > > How is that? It's either the action attribute of a form, then the FORM > > says > > which one it is. Or it is not in a form, then it is a GET request. If the > > same URL is accessed both ways, then the server doesn't care which one it > > is. > > > > > Our current understanding is we have to use same method which we used > > for > > > first request/login. > > > > If you mean "method object", then you are wrong. HttpClient method objects > > can not be re-used, or at least should not. There were some methods for > > re-using, but it is rather pointless to try. Just create a new one. > > > > > Becuase it is storing the actual connection and session. > > > > The connection is kept in the method so you can release it when you're > > done with the response. The connection manager will try to keep the > > connection alive for the next request, but that is strictly a performance > > optimization. > > The session is in no way related to a connection. Session cookies are > > stored > > in the HttpState. If you didn't create an extra HttpState, the default > > state > > in the HttpClient will be used. > > > > I recommend that you create a new method object to access the second link, > > and execute it with the same HttpClient object as the first one. Don't > > forget to release the connection after each request, but not before you're > > done with reading the response. > > > > hope that helps, > > Roland > > > > --------------------------------------------------------------------- > > To unsubscribe, e-mail: [EMAIL PROTECTED] > > For additional commands, e-mail: [EMAIL PROTECTED] > > > > > >
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