Hmm. How come my message didn't show up after 2 hours..?
On Fri, Jun 27, 2008 at 10:43 AM, Yan aka. Yansheng <[EMAIL PROTECTED]>
wrote:
> Hi There,
>
> This is my first post here so I hope this is the right audience.
>
> My story: I want to replace a chunk of my code for doing I/O streaming to a
> webservice. I use java.net.HttpURLConnection to get the InputStream and
> OutputStream, it works fine most of the time but it can get a bit flaky and
> I had to write my own retry logic. So I decided to switch to
> jakartacommons-httpclient to see if things get better. The problem is I
> don't seem to be able to come up with a good replacement from the httpclient
> package.
>
> Here is the method for obtaining a HttpConnection I wrote, the problem is
> the HostConfiguration returned is not populated.
>
> --------
> private HttpConnection openConnection(URL url) throws IOException {
> HttpMethod method = new PostMethod(url.toString());
> HttpConnection conn = null;
>
> // Execute the method.
> int statusCode = getHttpClient().executeMethod (method);
>
> if (statusCode != HttpStatus.SC_OK) {
> method.releaseConnection();
> throw new IOException("Unable to connect to Service: " + url);
> }
> else {
> HttpConnectionManager connManager =
> client.getHttpConnectionManager();
> conn =
> connManager.getConnection(client.getHostConfiguration());
> }
>
> return conn;
> }
> -------
>
> The exception I'm getting:
>
> Exception in thread "main" java.lang.IllegalArgumentException: host
> parameter is null
> at
> org.apache.commons.httpclient.HttpConnection.setHost(HttpConnection.java:248)
> at
> org.apache.commons.httpclient.SimpleHttpConnectionManager.getConnectionWithTimeout(SimpleHttpConnectionManager.java:163)
> at
> org.apache.commons.httpclient.SimpleHttpConnectionManager.getConnection(SimpleHttpConnectionManager.java:191)
> at
> org.apache.commons.httpclient.SimpleHttpConnectionManager.getConnection(SimpleHttpConnectionManager.java:108)
> at
> amazon.wma.storage.timber.TimberServiceImpl.openConnection(MyServiceImpl.java:180)
> ...
>
> Thanks for any help!
> Yansheng
>
