Proxy with optional basic authentication. We have a ServerComm class
that contains server connection info. You should be
able to figure out what it is doing.
---> START
DefaultHttpClient cli = new DefaultHttpClient();
HttpGet method = null;
HttpHost targetHost = null;
HttpHost proxy = null;
if (ServerComm.UseProxy )
{
if ( ServerComm.UseProxyAuth)
{
cli.getCredentialsProvider().setCredentials(
new AuthScope(ServerComm.ProxyAddress,
ServerComm.ProxyPort),
new
UsernamePasswordCredentials(ServerComm.ProxyUser, ServerComm.ProxyPw)
);
}
targetHost = new HttpHost(ServerComm.GetServerSite(),
ServerComm.ServerPort, ServerComm.Method);
proxy = new HttpHost(ServerComm.ProxyAddress, ServerComm.ProxyPort);
cli.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY, proxy);
try {
URI newUri = new URI(ServerComm.GetServerUrl());
method = new HttpGet(newUri.getRawPath() + "?" +
newUri.getRawQuery());
} catch (URISyntaxException ex) {
System.out.println("URI Encode Error " + ex.toString());
isCorrect = false;
return false;
}
}
else
{
method = new HttpGet(ServerComm.GetServerUrl());
}
HttpResponse resp = null;
HttpEntity ent = null;
method.addHeader("User-Agent", ServerComm.MDOUserAgent);
//execute the method
String responseBody = null;
try{
if (ServerComm.UseProxy )
{
resp = cli.execute(targetHost,method);
}
else
{
resp = cli.execute(method);
}
ent = resp.getEntity();
}
<--- END
On Thu, Jan 24, 2013 at 4:13 PM, Kevin Weslowski <[email protected]> wrote:
> I searched the archives but I can't seem to find it...if you can find it,
> please send me a link...thanks...
>
> ----- Original Message -----
> From: "David J. Godbey (HQ-LM020)[DIGITAL MANAGEMENT INC.]"
> <[email protected]>
> To: "HttpClient User Discussion" <[email protected]>
> Sent: Thursday, January 24, 2013 2:37:17 PM GMT -06:00 Central America
> Subject: RE: connect through proxy
>
> Did you see my problem/solution regarding NTLMv2 proxy authentication? You
> could probably do something like that. That thread appeared around October 11.
>
> -----Original Message-----
> From: Kevin Weslowski [mailto:[email protected]]
> Sent: Thursday, January 24, 2013 3:12 PM
> To: HttpClient User Discussion
> Subject: Re: connect through proxy
>
> thanks, but I couldn't get that to work for me.
>
> I did some research and I have the same problem as found in this post:
>
> http://stackoverflow.com/questions/13308073/httpcomponents-client-proxy-problems
>
> and the suggested solution doesn't work for me...
>
> ----- Original Message -----
> From: "Mark Claassen" <[email protected]>
> To: "HttpClient User Discussion" <[email protected]>
> Sent: Thursday, January 24, 2013 12:45:42 PM GMT -06:00 Central America
> Subject: RE: connect through proxy
>
> I don't know too much about authenticating proxies. Is it possible that the
> authentication is done via some magic from your OS? I know to get my
> Webstart stuff to work right I needed to also use the java "native" socket
> factory. You can try this and see if it helps.
>
> In HttpClient 4.2:
>
> fact = new
> SSLSocketFactory(HttpsURLConnection.getDefaultSSLSocketFactory(),ver);
> new Scheme(protocol, port , fact);
>
>
> -----Original Message-----
> From: Kevin Weslowski [mailto:[email protected]]
> Sent: Thursday, January 24, 2013 1:23 PM
> To: HttpClient User Discussion
> Subject: Re: connect through proxy
>
> ok, I tried this:
> ========================
> HttpParams params = new BasicHttpParams();
> params.setParameter(ConnRoutePNames.DEFAULT_PROXY, new
> HttpHost("myproxyserver", 8080)); ClientConnectionManager cm = new
> BasicClientConnectionManager(); HttpClient httpclient = new
> DefaultHttpClient(cm, params); HttpGet httpGet = new
> HttpGet("http://www.google.com"); HttpResponse response1 =
> httpclient.execute(httpGet); System.out.println(response1.getStatusLine());
> ========================
> But the output is always: HTTP/1.1 407 Proxy Authentication Required (
> Forefront TMG requires authorization to fulfill the request.
> Access to the Web Proxy filter is denied. )
>
> I didn't need credentials in my earlier Java program...why not there and why
> now here? And any ideas how to fix this?
>
> ----- Original Message -----
> From: "Jean-Marc Spaggiari" <[email protected]>
> To: "HttpClient User Discussion" <[email protected]>
> Sent: Thursday, January 24, 2013 11:19:29 AM GMT -06:00 Central America
> Subject: Re: connect through proxy
>
> This piece of code is working for me:
>
> HttpParams params = new BasicHttpParams();
> params.setParameter(ConnRoutePNames.DEFAULT_PROXY, new
> HttpHost(proxyhostname, 80)); client = new DefaultHttpClient(cm, params);
>
> You might want to look at something similar.
>
> JM
>
> 2013/1/24, Kevin Weslowski <[email protected]>:
>> Hi,
>>
>> I have some URLConnection code that connects through a proxy:
>> ============================
>> java.net.URL url = new java.net.URL("http://www.google.com");
>> java.net.SocketAddress sa = new
>> java.net.InetSocketAddress("myproxyserver",
>> 8080);
>> java.net.Proxy proxy = new java.net.Proxy(java.net.Proxy.Type.HTTP,
>> sa); java.net.HttpURLConnection con = (java.net.HttpURLConnection)
>> url.openConnection(proxy); ============================ and I want to
>> convert that to equivalent httpclient code but I can't seem to find
>> the right way to do that. Can someone point me in the right direction?
>> Thanks...
>>
>> Kevin
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: [email protected]
>> For additional commands, e-mail: [email protected]
>>
>>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [email protected]
> For additional commands, e-mail: [email protected]
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [email protected]
> For additional commands, e-mail: [email protected]
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [email protected]
> For additional commands, e-mail: [email protected]
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [email protected]
> For additional commands, e-mail: [email protected]
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [email protected]
> For additional commands, e-mail: [email protected]
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [email protected]
> For additional commands, e-mail: [email protected]
>
---------------------------------------------------------------------
To unsubscribe, e-mail: [email protected]
For additional commands, e-mail: [email protected]