Keith,

The # character is reserved to separate the fragment from the query/path. The fragment is not intended to be sent over the wire. So if you want to include such a character in an URI you should URL-escape it with %23:

http://localhost:8081/axis2/services/ProbeDataService.RawParameterEndpoint/RawParameter%23id

Does that work for you?

Ortwin

keith chapman wrote:
Hi,

I want to send a http GET request to the followin url

http://localhost:8081/axis2/services/ProbeDataService.RawParameterEndpoint/RawParameter#id

But i have to set a URI to the getMethod.

I have the above as a URL. So I do the following

getMethod.setURI(url.toString);

This rips off the fragment part resulting in the following target URL

http://localhost:8081/axis2/services/ProbeDataService.RawParameterEndpoint/RawParamete

How can I send a fragment in the url?

Thanks,
Keith


--
[web]  http://www.odi.ch/
[blog] http://www.odi.ch/weblog/
[pgp]  key 0x81CF3416
       finger print F2B1 B21F F056 D53E 5D79 A5AF 02BE 70F5 81CF 3416

---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]

Reply via email to