Hi Jerzy,
| > div 1 (-2)
| -1
| > div (-1) 2
| -1
|
| but
| > div (-1) (-2)
| 0
| > div 1 2
| 0
| > div 0 (-2)
| 0
No errors here. Check the Haskell report for properties of div:
"The quot, rem, div, and mod class methods satisfy these laws:
(x `quot` y)*y + (x `rem` y) == x
(x `div` y)*y + (x `mod` y) == x
`quot` is integer division truncated toward zero, while the
result of `div` is truncated toward negative infinity."
Perhaps you were expecting div to be like quot?
All the best,
Mark
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