Didn't you base your estimation on the leakage losses from power grid
distributions?
That would make more sense- as the higher German figure is getting
rather too big and is only based on an arbitary depth of penetration,
by the looks of it. [& 15+ times higher]
Most Hum we discuss seems to be at elevated levels above ground anyway
and be building related via nodes. This posits a non linear
distribution which would reduce power needs substantially too.
I reckon the german work is the power of kite string hum -flying high
in the stratosphere :)
[Joking apart- all ideas are worth considering and this is just my
'one off' view.]


On Jun 26, 9:57 am, "john dawes" <[email protected]> wrote:
> By observing the movement of a small mass attached to a spring, I have 
> estimated that the energy required to produce the Hum across known areas of 
> the UK is
>
> 350 Kilowatts/ square kilometre.
>
> A German investigator, using a completely different approach gives a figure of
>
> 5.4 Megawatts/ square kilometre
>
> His approach is this.
>
> Germany has an area of 35711.9 square kilometres. Vibration can occur in a 
> small basement of 2 metres which would give
>
> 35711.9 * 1000 * 1000 * 2 = 7.14 * 10E11 cubic metres of earth being vibrated.
>
> Weight of a cubic metre of earth 1700 kg
>
> Total mass of vibrating earth 1.12 * 10E15
>
> Assuming the amplitude of vibration to be .0001 metre the potential energy 
> would be
>
> 1.12 * 10E15 * 9.8 * .0001 = 1.19 * 10E12 Newton metres
>
> With a 30 Hz hum the vibration of one cycle would be .0017 seconds therefore 
> the power requirement for Germany would be
>
> 1.19 * 10E12 * .0017 = 1.98 * 10E5 Megawatts.
>
> Any other bids?
>
> The information game from a German open forum web site.
>
> http://f3.webmart.de/f.cfm?id=234287

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