vaibhav dutt, le Tue 21 Feb 2012 19:59:54 +0100, a écrit : > The following is the Hardware topology of the compute node I am using, a > obtained > by using lstopo. > > Machine (16GB) > Socket L#0 > L2 L#0 (6144KB) > L1 L#0 (32KB) + Core L#0 + PU L#0 (P#0) > L1 L#1 (32KB) + Core L#1 + PU L#1 (P#4) > L2 L#1 (6144KB) > L1 L#2 (32KB) + Core L#2 + PU L#2 (P#2) > L1 L#3 (32KB) + Core L#3 + PU L#3 (P#6) > Socket L#1 > L2 L#2 (6144KB) > L1 L#4 (32KB) + Core L#4 + PU L#4 (P#1) > L1 L#5 (32KB) + Core L#5 + PU L#5 (P#5) > L2 L#3 (6144KB) > L1 L#6 (32KB) + Core L#6 + PU L#6 (P#3) > L1 L#7 (32KB) + Core L#7 + PU L#7 (P#7) > > It has 4 cores on each socket. But the cores like(0 and 4, 1 and 5 etc.) > are to be considered on the same die?
0 and 4 share the same L2 cache, and are on the same socket as 2 and 6. Use lstopo -.txt, it'll probably be clearer. Samuel
