Hello

We only add hwloc Group objects when necessary. On your system, each
processor group contains a single NUMA node, so these Groups would not
really bring additional information about the hierarchy of resources.
If you had a bigger system with, let's say, 4 NUMA nodes, with 2 of them
in each processor groups, hwloc would report those as hwloc Group objects.

Does this help? I can clarify the FAQ if needed.

Brice



Le 29/11/2017 14:25, David Creasy a écrit :
> Hello,
>
> Thank you to all contributors to hwloc - very useful.
>
> In the FAQ,  under the section "What are these Group objects in my
> topology?" it says that they are used for "Windows processor groups".
> However, I'm either not seeing this, or I'm looking in the wrong
> place. On a system with two processor groups, I get:
>
> C:\temp\hwloc-win64-build-1.11.8\bin>hwloc-info.exe
> depth 0:        1 Machine (type #1)
>  depth 1:       2 NUMANode (type #2)
>   depth 2:      2 Package (type #3)
>    depth 3:     2 L3Cache (type #4)
>     depth 4:    12 L2Cache (type #4)
>      depth 5:   12 L1dCache (type #4)
>       depth 6:  12 L1iCache (type #4)
>        depth 7: 12 Core (type #5)
>         depth 8:        24 PU (type #6)
>
> C:\temp\hwloc-win64-build-1.11.8\bin>hwloc-ls.exe
> Machine (1506MB total)
>   NUMANode L#0 (P#0 346MB) + Package L#0 + L3 L#0 (12MB)
>     L2 L#0 (256KB) + L1d L#0 (32KB) + L1i L#0 (32KB) + Core L#0
>       PU L#0 (P#0)
>       PU L#1 (P#1)
>     L2 L#1 (256KB) + L1d L#1 (32KB) + L1i L#1 (32KB) + Core L#1
>       PU L#2 (P#2)
>       PU L#3 (P#3)
>     L2 L#2 (256KB) + L1d L#2 (32KB) + L1i L#2 (32KB) + Core L#2
>       PU L#4 (P#4)
>       PU L#5 (P#5)
>     L2 L#3 (256KB) + L1d L#3 (32KB) + L1i L#3 (32KB) + Core L#3
>       PU L#6 (P#6)
>       PU L#7 (P#7)
>     L2 L#4 (256KB) + L1d L#4 (32KB) + L1i L#4 (32KB) + Core L#4
>       PU L#8 (P#8)
>       PU L#9 (P#9)
>     L2 L#5 (256KB) + L1d L#5 (32KB) + L1i L#5 (32KB) + Core L#5
>       PU L#10 (P#10)
>       PU L#11 (P#11)
>   NUMANode L#1 (P#1 1160MB) + Package L#1 + L3 L#1 (12MB)
>     L2 L#6 (256KB) + L1d L#6 (32KB) + L1i L#6 (32KB) + Core L#6
>       PU L#12 (P#64)
>       PU L#13 (P#65)
>     L2 L#7 (256KB) + L1d L#7 (32KB) + L1i L#7 (32KB) + Core L#7
>       PU L#14 (P#66)
>       PU L#15 (P#67)
>     L2 L#8 (256KB) + L1d L#8 (32KB) + L1i L#8 (32KB) + Core L#8
>       PU L#16 (P#68)
>       PU L#17 (P#69)
>     L2 L#9 (256KB) + L1d L#9 (32KB) + L1i L#9 (32KB) + Core L#9
>       PU L#18 (P#70)
>       PU L#19 (P#71)
>     L2 L#10 (256KB) + L1d L#10 (32KB) + L1i L#10 (32KB) + Core L#10
>       PU L#20 (P#72)
>       PU L#21 (P#73)
>     L2 L#11 (256KB) + L1d L#11 (32KB) + L1i L#11 (32KB) + Core L#11
>       PU L#22 (P#74)
>       PU L#23 (P#75)
>
> I definitely have 2 processor groups:
> C:\Windows\system32>bcdedit /enum | find "group"
> groupsize               6
> maxgroup                Yes
>
> And you can see this because the processor numbers above in the second
> numa node start at 64. Also, calling GetActiveProcessorGroupCount()
> returns 2.
>
> I was expecting to get "2" back from:
> hwloc_get_nbobjs_by_type(hwlocTopology_, HWLOC_OBJ_GROUP)
>
> but that returns 0. Am I doing something wrong?
>
> Thank you!
>
> David
>

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