The problem is with the (year/4) it should be (year//4) That is
5 *-* day = (year + (year // 4) + jday) // 7 >V> "2003" >V> "2003" >L> "4" >O> "3" >O> "2006" >V> "147" >O> "2153" >L> "7" >O> "4" Kenneth Leidner Imagination is more important than knowledge. -----Original Message----- From: IBM Mainframe Discussion List [mailto:[EMAIL PROTECTED] On Behalf Of Baraniecki, Ray Sent: Thursday, May 26, 2005 3:09 PM To: [email protected] Subject: Rexx Question I am performing the following instructions " If year > "1900" Then year = year - 1 day = (year + (year / 4) + jday) // 7" in the hope of receiving an answer ranging from 1 through 7. When the year = 2004 and the julian day = 147 I get a result of 4.75. I was expecting an answer of 4 which would indicate Wednesday. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
