In a message dated 7/20/2005 4:32:17 P.M. Central Daylight Time,  
[EMAIL PROTECTED] writes:

You are  correct as far as it goes.

What you are not taking into consideration  is the overhead applied by the 
DASD controller to each physical  block.

A complete calculation must take into consideration Record Zero  + 255 Data 
Areas + 255 Count Areas + (Optionally) 255 Key Areas + all of the  associated 
inter-block gaps.




New controller microcode would be needed to allow 255 records, each of  which 
was 65535 bytes long with a possibly 255-byte-long key, to occupy the same  
one virtual track.  Given the need for new microcode, why must we continue  the 
legacy of overhead for R0, count areas, and gaps?  Let the new virtual  track 
size be as large as it needs to be.  So maybe it exceeds 16MiB by a  few 
thousand bytes and thus needs more than 24 bits.  Who cares?  It's  all virtual 
and being mapped onto real disks through complex mapping  algorithms.
 
Bill Fairchild


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In a message dated 7/20/2005 4:32:17 P.M. Central Daylight Time,  
[EMAIL PROTECTED] writes:

You are  correct as far as it goes.

What you are not taking into consideration  is the overhead applied by the 
DASD controller to each physical  block.

A complete calculation must take into consideration Record Zero  + 255 Data 
Areas + 255 Count Areas + (Optionally) 255 Key Areas + all of the  associated 
inter-block gaps.




New controller microcode would be needed to allow 255 records, each of  which 
was 65535 bytes long with a possibly 255-byte-long key, to occupy the same  
one virtual track.  Given the need for new microcode, why must we continue  the 
legacy of overhead for R0, count areas, and gaps?  Let the new virtual  track 
size be as large as it needs to be.  So maybe it exceeds 16MiB by a  few 
thousand bytes and thus needs more than 24 bits.  Who cares?  It's  all virtual 
and being mapped onto real disks through complex mapping  algorithms.
 
Bill Fairchild

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