In <[EMAIL PROTECTED]>, on 09/13/2005
at 03:22 AM, john gilmore <[EMAIL PROTECTED]> said:
>There is no need to use a simplified or 'linear' leap-year
>correction calculation. For any algebraic Gregorian year value y
>the exact signed number of leap-year correction days in preceding
>years is easily calculated by the method of inclusions and
>exclusions. It is just
>C(y) = 365(y - 1)
> + (y - 1)//4
> - (y - 1)//100
> + (y - 1)//400
>in which '//' denotes remainder-discarding binary-integer
>division.
For the next few years, yes. Eventually there will be a need for an
additional adjustment.
--
Shmuel (Seymour J.) Metz, SysProg and JOAT
ISO position; see <http://patriot.net/~shmuel/resume/brief.html>
We don't care. We don't have to care, we're Congress.
(S877: The Shut up and Eat Your spam act of 2003)
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