Guess I am missing something: I specified HVCOMMON=2G in ieasys(za). No error message during IPL, and D VS,HVCOMMON now shows: D VS,HVCOMMON IAR019I 07.55.06 DISPLAY VIRTSTOR 239 SOURCE = ZA TOTAL 64-BIT COMMON = 4G 64-BIT COMMON RANGE = 2044G-2048G 64-BIT COMMON ALLOCATED = 1M
Why are 4G allocated? How do I get exactly 2G? According to all books/presentations, 2G is the minimum. And no, we're a small installation, and I don't care about huge default areas that can bring down my paging subsystem if misused by any runaway application or system code. Regards, Barbara Nitz ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
