> -----Original Message-----
> From: IBM Mainframe Discussion List
> [mailto:[EMAIL PROTECTED] On Behalf Of John Krew
> Sent: Monday, November 21, 2005 1:42 PM
> To: [email protected]
> Subject: Displaying hexdecimal content of field in Cobol
>
>
> Aside from writing and CALLing a trivial assembler routine,
> is there any way to display the
> hexadecimal content of a field in a COBOL program using COBOL syntax?
>
> John Krew
The easiest way, to me, is to transliterate the HLASM program, as
follows:
WORKING-STORAGE SECTION.
01 TWO-VARS.
05 PACKED-VAR PIC S9(3) PACKED-DECIMAL.
05 CHAR-VAR REDEFINES PACKED-VAR
PIC XX.
77 OUTPUT-THREE PIC X(3).
77 OUTPUT-TWO PIC X(2).
77 I PIC S9(4) BINARY.
*
LOCAL-STORAGE SECTION.
LINKAGE SECTION.
01 MVS-PARM.
05 MVS-PARM-LENGTH PIC S999 USAGE BINARY.
05 MVS-PARM-VALUE PIC X(120) .
*
PROCEDURE DIVISION USING MVS-PARM.
START-UP.
PERFORM VARYING I FROM 1
BY 1
UNTIL I > MVS-PARM-LENGTH
MOVE ZERO TO PACKED-VAR
MOVE MVS-PARM-VALUE (I:1) TO CHAR-VAR (1:1)
MOVE PACKED-VAR TO OUTPUT-THREE
MOVE OUTPUT-THREE (1:2) TO OUTPUT-TWO
INSPECT OUTPUT-TWO
CONVERTING X"F0F1F2F3F4F5F6F7F8F9FAFBFCFDFEFF"
TO
'0123456789ABCDEF'
DISPLAY MVS-PARM-VALUE (I:1) ' '
OUTPUT-TWO ' '
OUTPUT-THREE
UPON SYSOUT
END-PERFORM
--
John McKown
Senior Systems Programmer
UICI Insurance Center
Information Technology
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