The answer is definitely number of CPUs times 60*10. But another interesting question might be "how many CPU seconds can I see represented in control blocks and/or SMF records". And the answer to that question will rely on whether you are running with full-speed processors and have zAAPs/zIIPs since, depending on the control block you are examining, time running on a zAAP/zIIP might be normalized to the speed of the standard CP (hence multiplied). ASCBEJST is one such field. TCBTTIME is another.
If for example you have one zAAP and one standard CP, and the zAAP runs twice as fast as a standard CP, and if both zAAP and CP are fully busy, the total time represented would be up to 3 CPU's worth of seconds even though you only have two CPUs. Peter Relson z/OS Core Technology Design ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
