Sir,
Negative ...
ICM first_operand,B'third_operand',0(second_operand)
Actually ... 'third_operand' is not really defined as an operand more
so as 'M3' ... mask.
If 'second_operand' points to the value x'aabbccdd' in storage then ICM
will copy x'aabbcc' to 'first_operand' given that the 'third_operand'
or 'M3' is b'0111' (or 7). This will result in the 'first_operand' being
x'yyaabbcc' where 'yy' would be a result of residual usage previously.
Kind Regards
Jim Thomas
617-233-4130 (mobile)
636-294-1014 (res)
[email protected] (Email)
-----Original Message-----
From: IBM Mainframe Discussion List [mailto:[email protected]] On Behalf
Of Chase, John
Sent: Friday, August 05, 2011 3:02 PM
To: [email protected]
Subject: Re: assembler help!
In the example cited below, operand 3 starts at location 00000008.
> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:[email protected]] On
Behalf Of Lloyd Fuller
> Sent: Friday, August 05, 2011 2:39 PM
> To: [email protected]
> Subject: Re: assembler help!
>
> No.
>
> ICM ..,7,.. is going to load from the leftmost 24 bits of operand 3
NOT from
> the rightmost 24 bits. BTDT and had to fix it.
>
> Lloyd
>
>
>
>
> ----- Original Message ----
> From: Tom Marchant <[email protected]>
> To: [email protected]
> Sent: Fri, August 5, 2011 3:25:02 PM
> Subject: Re: assembler help!
>
> On Fri, 5 Aug 2011 13:24:50 -0500, Jim Thomas wrote:
>
> >please note that the mask value for an ICM represent the
> >locations of the receiving register. If the sending address is
> >x'00000008', then ICM is going to look at address x'00000000' thru
> >x'00000002'.
>
> ITYM locations x'08' through x'0A'.
>
> --
> Tom Marchant
>
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