As of z/OS 1.7 JES2 you can use the command:
$LJQ,OUTGRPS
to display the number of JOEs for all jobs on the system.  On a test system
you would see:
STC00001  $HASP891 OUTPUT($MASCOMM)  OUTGRPS=0
STC00002  $HASP891 OUTPUT(IRRDPTAB)  OUTGRPS=1
STC00003  $HASP891 OUTPUT(ZFS)       OUTGRPS=0
STC00004  $HASP891 OUTPUT(SYSLOG)    OUTGRPS=0
STC00006  $HASP891 OUTPUT(INIT)      OUTGRPS=0
STC00007  $HASP891 OUTPUT($JESNEWS)  OUTGRPS=0
STC00008  $HASP891 OUTPUT(RACF)      OUTGRPS=0
STC00009  $HASP891 OUTPUT(DEALLOC)   OUTGRPS=1
STC00010  $HASP891 OUTPUT(BPXAS)     OUTGRPS=0
STC00011  $HASP891 OUTPUT(BPXAS)     OUTGRPS=0
STC00012  $HASP891 OUTPUT(BPXAS)     OUTGRPS=0
STC00013  $HASP891 OUTPUT(BPXAS)     OUTGRPS=0

You can also filter on OUTGRPS so on the same system you can issue the command
$ljq,outgrps>0,outgrps 
and get the output
STC00002  $HASP891 OUTPUT(IRRDPTAB)  OUTGRPS=1
STC00009  $HASP891 OUTPUT(DEALLOC)   OUTGRPS=1

Of course you can use a larger number in the command
$ljq,outgrps>50,outgrps
STC15576 $HASP891 OUTPUT(DVGSRV01)  OUTGRPS=204
STC15577 $HASP891 OUTPUT(DVGSRV02)  OUTGRPS=171
STC15578 $HASP891 OUTPUT(DVGSRV03)  OUTGRPS=148

See the $LJ command for more information on other filters available in 1.7

Tom Wasik
IBM JES2 Development

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