Agreed! Over the course of forty years, I've never known anybody
who thinks that COND= is intuitive. I always mentally rearrange it to
state "BYPASS THIS STEP IF" but your SKIP= works well too.
From: "Jeffrey D. Smith" <[EMAIL PROTECTED]>
Reply-To: IBM Mainframe Discussion List <[email protected]>
To: [email protected]
Subject: Re: COND= running a step that it should not. WHY? BFOM! Options
Date: Tue, 7 Aug 2007 13:34:59 -0600
Actually, any RC>=9 will skip the step. I always have to rethink the
COND= to mean SKIP=. That is, if the condition holds true, then SKIP
the step. My brain implicitly tries to think the opposite, that the
step should execute only if the condition is true. It's really a
conditional SKIP expression. Weird.
/J
> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:[EMAIL PROTECTED] On
> Behalf Of J R
> Sent: Tuesday, August 07, 2007 1:23 PM
> To: [email protected]
> Subject: Re: COND= running a step that it should not. WHY? BFOM! Options
>
> The step should be executed unless any prior step has RC>9.
>
>
> Neal Eckhardt said:
> >OK, I'm usually pretty good at spotting these things, but this one has
me
> >baffled.
> >
> >z/OS 1.4 system and here is the JCL setup
> >
> >
> >Job card with COND=(9,LT).
> >
> >
> >An IF/THEN/ELSE/ENDIF construct with another IF/THEN/ELSE/ENDIF imbeded
> in
> >the first one.
> >
> >
> >A PROC that has an override COND.STEPX=(4,LT,SORT0035) for a step
within
> >the PROC, and the above mentioned IF/THEN/ELSE/ENDIF is also contained
> >within the PROC.
> >
> >
> >Following the outer IF/ENDIF construct, outside of the PROC is a step
> with
> >COND=(9,LT). This step is executing. Looking at all of the Return Codes
> for
> >this execution, all steps finished with a RC=0 except for one step that
> >ended with a RC=4. Several steps were FLUSHED due to the IF/ENDIF
> testing.
> >
> >
> >For the life of me, I cannot see why this step is running.
> >
> >
> >Can anybody throw ANY ideas my way to explain this?
> >
> >
> >Thanks, Neal
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