Todd,
The service units for a task are actually derived from the CPU time, not the
other way around.
Rather than using tables you should use the SU_SEC from the from the LPAR
you are running in, as the value can change depending on the number of
online processors.
With kudos to Barry Merrill, the following used to work:
The following method of determining the proper CPU speed
coefficient with the TSO TEST command was adapted from Volume 4,
Number
8 (April 15, 1982) of the Candle Computer Report:
TEST 'SYS1.LINKLIB(IEFBR14)'
L 10.%+25C?+40 F for MVS/XA
L 10.%+25C%+40 F for MVS/370
Note: the % operator indicates 24-bit indirect addressing, which
will
not work for a control block above 16MB. Thus, ? (31-bit indirect
addressing) must be used in place of the last % only for MVS/XA.
The LIST (L) command will display:
HHHHHHHH NNNNNN
where HHHHHHHH is the hex address of the (decimal) constant NNNNNN.
Then:
SU_SEC = (16,000,000) / NNNNNN
Also check that the Service Units value you have only includes the counters
for CPU Time that you wish to report. As others have said, it would be much
easier to get the CPU time directly from the Type 30 SMF records.
Ron
> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:[EMAIL PROTECTED] On
> Behalf Of Todd Burrell
> Sent: Tuesday, May 06, 2008 6:05 AM
> To: [email protected]
> Subject: [IBM-MAIN] Service Unit to CPU minute conversion
>
> I have a request from management to give them the number of CPU minutes
> used for a certain time period per application. I have the numbers for
> numbers
> of service units for each period and application, but I need to know
> what
> conversion factor I can use to convert this to CPU minutes? Is there a
> manual that walks me through this process? Also, we are on a 2064-102.
> which I would think would be a factor in the conversion process. I
> seem to
> remember that service units apply based on a machine type?
>
> I looked through the archives and did not see anything that
> specifically
> addressed this, so I figured I'd ask the group.
>
> Thanks
>
> Todd Burrell
>
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