However, as mentioned if you are expecting the value to later be used as null-terminated string, you need to add Dest[8] = 0x00; Or the value of the byte after the ending 'L' is un-predictable.
Wayne Driscoll Product Developer NOTE: All opinions are strictly my own. -----Original Message----- From: IBM Mainframe Discussion List [mailto:[EMAIL PROTECTED] On Behalf Of Staller, Allan Sent: Monday, September 08, 2008 1:49 PM To: [email protected] Subject: Re: question for C experts - strcpy vs memcpy <snip> If I am copying literal text into a char array, which do you think is better: strcpy(dest,"LITERAL"); OR memcpy(dest,"LITERAL",8); </snip> FWIW, IIRC, strcpy will copy until a x'00 is encountered. This results in a "variable length" copy. If no x'00' is encountered, strcpy will happily copy all of storage until it tries to access un-owned storage, at which time there will be a S0C4 (U4039 in LE terms) abend. Memcpy will copy storage for the length indicated. I concur with the other poster (and yourself) that memcpy is the preferred method. HTH, ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
