On Wed, 17 Sep 2008 09:30:08 EDT, IBM Mainframe Discussion List <[EMAIL PROTECTED]> wrote:
> > >From the article on Stretch: >"[Stretch] ... could perform 100 billion computations a day and handle half >a million instructions per second." > >There are 86400 seconds in one day. Half a million instructions per second >for one day equals 43 billion instructions, which somehow were able to >perform 100 billion computations. I don't know of any z/OS instructions that can >perform more than one computation per instruction, but I must confess I >haven't read about all the newest ones yet. How was Stretch able to perform over >two computations for each instruction handled? FWIW, according to Wikipedia Stretch ended up performing 1.2 MIPS. -- Walt ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
