---------------------------------<snip>--------------------------
I have to agree. It is hard to believe that such a talented group of
people can construct a Rube Goldberg so quickly.
The OP asked how to calculate the size of the file in MB or GB. Gadi
responded with the exact answer:
"A track on a 3390 type disk has 56,664 bytes. If you multiply the
number of tracks (297,141) by that you get 16,837,197,624 or about 16GB."
What other answer could there possibly be? He did not ask how many MB
would it use on Windows or *NIX. He did not ask how big is the file
after removing block gaps.
If you allocate the file using MB notation it will be converted to
tracks based on 56664 bytes. Ipso facto tracks times 56664 gives you the
size in MB on an MVS system.
-----------------------------<unsnip>-------------------------------
Ron, I disagree. The OP posted a non-optimal BLKSIZE value and that can
make a BIG difference in the number of tracks required, as you well
know. And the presence of absence of interblock gaps can make a HUGE
difference. Bytes of data vs. space utilized can be vastly different if
inefficient methods/sizes are used.
I have to go along with this calculation:
(Bytes per block) * (Blocks per track) * total number of tracks
as yielding a far more accurate value.
Happy Holidays to all our friends on this list, and also to Darren and
his family.
--
Rick
--
Remember that sone days you're the pigeon, other days you're the statue.
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