I am failing to understand something about the code generation that the Enterprise COBOL compiler (V3.4.1) performs. For a WORKING-STORAGE variable defined like this:
77 WORK-WORD9 PIC S9(09) BINARY. with TRUNC(BIN) and OPTIMIZE(STD) in effect, this IF statement: IF (WORK-WORD9 < -1) OR (WORK-WORD9 > +256) Generates a bunch of code to convert WORK-WORD9 to packed decimal in temporary storage (and it does it *twice* no less!) to then do compare-packed for each of the literal values. How or why is it that the compiler does not just use binary constants for such a pair of comparisons? It just does not make any sense to me for the compiler to convert a fullword binary variable to packed in this case, and to do it twice for goodness sake. And secondly, if it really *has* to do the conversion, doesn't the optimizer realize it already did it already? The description of OPTIMIZE(FULL) doesn't sound like it will help here, though I will try it. OPTIMIZE(FULL) says it eliminates unreferenced WORKING-STORAGE but says nothing about better code optimization. Confused, Peter This message and any attachments are intended only for the use of the addressee and may contain information that is privileged and confidential. If the reader of the message is not the intended recipient or an authorized representative of the intended recipient, you are hereby notified that any dissemination of this communication is strictly prohibited. If you have received this communication in error, please notify us immediately by e-mail and delete the message and any attachments from your system. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
