So in REPORT07, you have: 0CL274. This will not reserve any storage, because the multiplier is zero. (7FE).
In the next variable, you have XL2. This is hex, length 2. Notice the location counter is at exactly the same place at REPORT07. (7FE). In the next variable you have XL2 again. This is hex, length 2. Notice the location counter has now increased by 2 (800). In the next variable, you have a Fullword. A fullword cannot start on a halfword boundary (802), so the assembler bumps the location counter to the next fullword (804). Same thing for your next two variables. Joe On Sat, Jul 4, 2020 at 2:48 PM Nguyen Dt <ndt....@gmail.com> wrote: > Dear lister, > I am learning assembler on my own, i have something strange that i can't > explain , please help me to understand > > Here is a section of my code : > > 608 DBLWORD DS D DBLE WORD > > 609 PATTERN6 DC X'402020202120' > 610 * > > 611 REPORTO7 DS 0CL274 > > 612 OW0007DB DS XL2 > > 613 OW0007OB DS XL2 > > 614 OW0007AC DS F > > 615 OW0007NP DS H > > 616 OW0007PT DS F > > 617 OW0007PF DS CL256 > > 618 * > > > > And here is the listing at compilation > > 0007FE 611 REPORTO7 DS 0CL274 > > 0007FE 612 OW0007DB DS XL2 > > 000800 613 OW0007OB DS XL2 > > 000804 614 OW0007AC DS F > > 000808 615 OW0007NP DS H > > 00080C 616 OW0007PT DS F > > > > I don't undestand why OW0007OB is 2 bytes , but on the left it is > considered as 4 bytes long , the same for QW0007NP > I read something with alignment obut it seems to concern constants , and > this is not constant ? > > > Thank you for clarification > > > ---------------------------------------------------------------------- > For IBM-MAIN subscribe / signoff / archive access instructions, > send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN > ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
