Thank you for all your hints and tips but I need just one command without an additional script or similar since I need this for different customers. All that I want is just create a file with some content and give that file "yesterdays" date. In each other Unix version not a problem at all, but USS seems to be different. The "date...--date" syntax is invalid in USS. As I said in my first post, I tried nearly everything I believe.....
HELP :-) -----Ursprüngliche Nachricht----- Von: IBM Mainframe Discussion List [mailto:[email protected]] Im Auftrag von Joel C. Ewing Gesendet: Donnerstag, 14. März 2013 17:15 An: [email protected] Betreff: Re: AW: USS "date" command, subtract one day Correct. So if you really want something that will work for all dates, including first of month, first of month in March on leap and nonleap year, first of year, etc. you need something else. I'm not enough of a UNIX authority to know if this is standard for all implementations of the UNIX date command and can't test in z/OS environment, but a search for "relative dates" and "Linux" found a "--date" parameter for the "date" command. At least on Fedora Linux the date command already appears to have relative date calculation built in. Currently (2013-03-14) on Fedora the command date --date="14 days ago" returns "Thu Feb 28 09:52:21 CST 2013" and date --date="379 days ago" returns "Wed Feb 29 09:57:26 CST 2012" If "date" under z/OZ UNIX supports the same parameters, then date +%Y%m%d --date="1 day ago" which today on Fedora returns "20130313" may be the form you need. JC Ewing On 03/14/2013 08:32 AM, Uwe Oswald wrote: > Thx perfect, thats exactly what I need. But I'm afraid this doesn’t work for > the first of a month for example 20130401 will then be 20130400 or I'm wrong? > > -----Ursprüngliche Nachricht----- > Von: IBM Mainframe Discussion List [mailto:[email protected]] > Im Auftrag von Rafal Hanzel ZETO Katowice > Gesendet: Donnerstag, 14. März 2013 13:23 > An: [email protected] > Betreff: Re: USS "date" command, subtract one day > > Maybe something like that, will help you: > echo "`date +%Y%m%d` - 1" | bc > > --- > Pozdrawiam/Best regards, > > Rafal Hanzel > Programista systemowy, Dział Badań i Rozwoju Systemów Komputerowych Tel. +48 > 32 3589246, Fax +48 32 3589277, email: [email protected] Tel. kom. +48 > 501677656 Zakład Elektronicznej Techniki Obliczeniowej w Katowicach Spółka z > o.o. > 40-158 Katowice, ul. Owocowa 1 > Sąd Rejonowy Katowice - Wschód w Katowicach Wydział VIII Gospodarczy > Krajowego Rejestru Sądowego, KRS 0000051477 Kapitał zakładowy: 264500 > zł NIP 634-013-11-06 http://www.zetokatowice.pl > > Jesteśmy uczestnikiem Programu > RZETELNA Firma > Sprawdź naszą rzetelność na > http://www.rzetelnafirma.pl/8FGKEVFH > > Treść tej informacji może być poufna, w związku z czym powinna trafić > bezpośrednio do rąk adresata. Jakiekolwiek jej ujawnianie, rozpowszechnianie, > bądź kopiowanie jest zabronione. W przypadku omyłkowego otrzymania niniejszej > informacji prosimy o poinformowanie nadawcy i usunięcie jej z komputera. > > W dniu 14.03.2013 12:54, Uwe Oswald napisał(a): >> Hi, >> >> I dont know if this is the right forum but I hope someone could help >> anyway. I want to subtract "one day" from the actual date with one >> USS unix command. >> >> The actual date I get via "date +%Y%m%d" (for example 20130314), but >> "date +%Y%m%d-1" or "...yesterday" don’t work. I have tried >> everything without success. Does anybody have a tip for me? It must >> be achieved within one command not more. >> >> Thx >> Uwe >> >> > -- Joel C. Ewing, Bentonville, AR [email protected] ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
