Peter thank you I did a TESTAUTH ‘JOER.TEST.AUTHLIB(CESTAE)’
Then at the TESTAUTH prompt Did LOAD ‘JOER.TEST.AUTHLIB(GRECOV)’ AT GRECOV.GRECOV.+0 Had a WAIT after the lock release Grecov did get control It had an SDWARBAD the X’40’ bit was on at the first status byte of the RB RBSTAB1 offset +A indicating an IRB Thanks for the info about branch entry ESTAE > On Mar 2, 2024, at 1:00 PM, Binyamin Dissen <[email protected]> > wrote: > > On Sat, 2 Mar 2024 06:21:34 -0800 Ed Jaffe > <[email protected]> wrote: > > :>On 3/2/2024 5:46 AM, Peter Relson wrote: > :>> Regarding the response about "why CIRB", it was not really on point. You > likely do not need to build/touch IQE/IRB. The parameters on SCHEDIRB (such > as EPPTR, MODE, KEY et al) generally cover all the pieces of data that you > would set in the IRB. They do cover all that you showed in your code example. > It is documented that SCHEDIRB is suggested rather than CIRB. > > :>Of course, I read about CIRB and the "exit effector" many times in the > :>pubs, but FWIW have always, Always, ALWAYS used SCHEDIRB in practice. > :>Never once coded CIRB nor ever been tempted to do so... > > Boomer. > > Some of us had to walk miles to find an IQE. > > -- > Binyamin Dissen <[email protected]> > http://www.dissensoftware.com > > Director, Dissen Software, Bar & Grill - Israel > > ---------------------------------------------------------------------- > For IBM-MAIN subscribe / signoff / archive access instructions, > send email to [email protected] with the message: INFO IBM-MAIN ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
