Thanks Peter and everybody! There was a lot of good information in this
thread, and I learned a few things. We already have COBOL programs being
used and supported for other things in this area, so I was tasked to
find a COBOL solution here.
Now, I have a working program and will set about seeing what the
resource needs are (even though this seems like a very fast call).
I appreciate all the input! See you next time!!!
Thank you and best regards,
Billy Ashton
------ Original Message ------
From "Farley, Peter" <[email protected]>
To [email protected]
Date 3/11/2025 11:18:27 AM
Subject Re: Using CSNBRNGL
Billy,
On this page IBM tells you how to set up the C language parameters. Wherever
this page says a parameter is “integer” it means “PIC S9(9) BINARY”, where it
says “string” it is any “PIC X” of at least the length specified by the
matching integer length parameter area. The integer random number output
“integer” for CSNBRNG is a 64-bit binary variable “PIC S9(18) BINARY”. For
CSNBRNGL is would be a “PIC X” area of the desired length (plus 21 if RT-KRD is
used).
https://www.ibm.com/docs/en/zos/2.4.0?topic=keys-random-number-generate-csnbrng-csnerng-csnbrngl-csnerngl
HTH
Peter
From: IBM Mainframe Discussion List <[email protected]> On Behalf Of
Billy Ashton
Sent: Tuesday, March 11, 2025 10:29 AM
To: [email protected]
Subject: Using CSNBRNGL
Hey all! It's been a while since I bothered y'all, and I hate to do this again, but my
manager wants me to do some research on using the Crypto feature to generate
"true" random numbers - CSNBRNGL.
He thinks this will help us get better, less predictable results for the places
we need to use random numbers, and he wants me to see how easy it is to use and
how many resources it might use.
As this is slated for possible COBOL use, has anyone used it in a COBOL
program, and would you share your data definition and code? I have spent hours
asking Dr. Google, and have gotten very little info about it. I found the
module in our linklist, so that part it easy, but I just can't figure out how
to call it.
I appreciate your help here!
Billy
Thank you and best regards,
Billy Ashton
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