> The issued PC is 16 bit linkage index (24 bit total with the entry number) but > the linkage state entry at offset +x'94' (decimal 148) has bits 0-11 zero. It > is described as the "Numeric Part of PC Number". Can the entire value be > returned from the linkage state entry?
Principles of Operation says: Numeric Part of PC Number: In a program-call state entry, bit positions 1-31 of bytes 148-151 contain the numeric part of the PC number used by the stacking PROGRAM CALL instruction that formed the entry. When ASN-and-LX reuse is not enabled, or when it is and bit 44 of the effective address used by stacking PROGRAM CALL is zero, stacking PROGRAM CALL places bits 44-63 of the effective address, with 11 zeros appended on the left, in bit positions 1-31 of bytes 148-151. When ASN-and-LX reuse is enabled and bit 44 of the effective address is one, stacking PROGRAM CALL places bits 45-63 of the effective address, with bits 32-43 of the effective address appended on the left, in bit positions 1-31 of bytes 148-151. In any case, stacking PROGRAM CALL places a zero in bit position 0 of the bytes if the resulting addressing mode is the 24-bit or 31-bit mode or a one in bit position 0 if the resulting addressing mode is the 64-bit mode. What part of the entire value is missing? Jim Mulder z/OS System Test IBM Corp. Poughkeepsie, NY ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
