Not sure if your question is intended to be serious but on an ANSI C
compiler there is no way to do substitution inside a literal string.
However, what could have been accomplished with this:
#define debug(a) printf("the value of a is %d\n", a)
that is, a macro that would print "the value of foo is 27"
can be accomplished with ANSI "stringification":
#define debug(a) printf("the value of %s is %d\n", #a, a)
The preprocessor turns #a into "foo" (including the quotes)
Charles
-----Original Message-----
From: IBM Mainframe Discussion List [mailto:[email protected]] On
Behalf Of Martin Packer
Sent: Friday, September 05, 2014 1:57 AM
To: [email protected]
Subject: Re: IBM C compiler substituting for macros inside literals?
So tell me, if one wanted to achieve this apparently non-standard effect how
WOULD one go about it?
Not that I want to but it HAD to be asked. :-)
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