Hi,
I executed IVSK instruction and got a value in bits 24 - 31 of R1 of X'A0' Looking at Pops book its say bits 24 - 31 are broken up as the following 24 - 27 is access control bit 28 fetch bit and 29 - 31 all zeros So that means X'A0' is storage key A (typically ranging from 0 - F) fetch bit is 0 ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
