I have a batch job and a couple of scripts that I've used in the past.
//BPX1 EXEC PGM=BPXBATCH,TIME=NOLIMIT,
// PARM='sh /u/myuserid/findpathfiles.sh /'
//STDOUT DD SYSOUT=*
//STDERR DD SYSOUT=*
//STDIN DD PATH='/u/myuserid/findpathfiles.sh'
// DD PATH='/u/myuserid/filesystemname'
The filesystemname:
set -x;
df -vk $1 | tail -1 | cut -c 16-41
exit 1
fi
the findpathfiles.sh:
set -x;
echo searching...
find $1 -type d -print -exec /u/myuserid/filesystemname {} \;
> /u/myuserid/listdirectories
The listdirectories would be populated if you executed the SH in OMVS.
This starts at /. All of the output goes into the STDOUT DD
-----Original Message-----
From: IBM Mainframe Discussion List [mailto:[email protected]] On Behalf
Of Lizette Koehler
Sent: Wednesday, November 01, 2017 1:35 PM
To: [email protected]
Subject: Help with a Unix process
So I am not very good with Unix, and now I need to find any file in a large
number of directories one directory has 130 directories with the tail .new (yep
clean up time)
So in OMVS I know the find / -name \*.new could work. But with the number of
directories I have to search it is not performing
I am thinking there could be a REXX in Unix written to do this. ls -al and
then search through the output
Maybe even using a grep.
But with so many of you other there with really awesome UNIX skills, what
should I, a novice, look at to be good performing, could be run in batch (Yep
like that
option) or produce a report in a file I can find that will show me all the
files in all the directories that have the tail I am looking for.
Thanks
Lizette Koehler
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