On Thu, Feb 1, 2018 at 11:11 AM, Charles Mills <[email protected]> wrote:
> > basically, /bin/sh is doing a UNIX "wait" command for the child > processes to complete. IOW, it is sleeping the sleep of the just. > > Well, yeah, it's waiting because it's waiting for something. > > But why so long? Would you really expect an ar to *always* take 2 minutes > or so on a z13s, even when it is lightly loaded? There are 213 object files > in the archive already. > Hum, an interesting question. I didn't really notice the "2 minutes" portion. I took a look at the ar command here: https://www.ibm.com/support/knowledgecenter/en/SSLTBW_2.3.0/com.ibm.zos.v2r3.bpxa500/libarc.htm And the only thing that came to my attention is that the "-r" switch adds or replaces one or more members __AND__ it "regenerates the symbol table". I don't really know what this latter is doing. But it may be why the "ar" command is taking a fairly fixed length of time (doing something with each member in the archive, not just the new one). I would likely test this by adding the same member to a different archive with fewer members. > > Charles > -- I have a theory that it's impossible to prove anything, but I can't prove it. Maranatha! <>< John McKown ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
