To be more pedantic, use additional parantheses:
ASXB = (int *) (((char *) ASCB) + 0x6c);
Kind regards
Bernd
Am 08.02.2018 um 20:47 schrieb Bernd Oppolzer:
int *ASCB;
int *ASXB;
ASXB = ASCB + 0x6c;
because ASCB is a pointer to int, and int has sizeof = 4,
you are in fact adding 4 * 0x6c to ASCB, that's your problem.
use the following notation, and it will work:
ASXB = (int *) ((char *) ASCB + 0x6c);
first you cast the ASCB to a char *, then you REALLY add 0x6c,
and then you cast the result back to int *.
That's C ... the other solutions suggested (templates etc.) are C++
and don't apply in your case.
HTH, kind regards
Bernd
Am 08.02.2018 um 17:45 schrieb Barkow, Eileen:
Thank you Charles and Seymore. I thought that the problem had
something to do with adding to pointers but
I could not find any doc about it in the manuals.
I am still not sure that I understand how to fix it but I will try
based on your info.
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