Call us cave men and see what it gets you!!! Regards, Richard Schuh
-----Original Message----- From: The IBM z/VM Operating System [mailto:[EMAIL PROTECTED] On Behalf Of Alan Altmark Sent: Wednesday, May 02, 2007 9:50 AM To: [email protected] Subject: Re: QUERY CAPABILITY question On Wednesday, 05/02/2007 at 09:02 MST, "Schuh, Richard" <[EMAIL PROTECTED]> wrote: > However, zero will be a limit --- and you need to multiply by 50% > (expressed as .5) to divide by 2. If you divide by .5, the result will > be an ever increasing value. (10 / .5 = 100 / 5 = 20) Now you guys cut that out! You know what I meant. Eventually everything turns to a value of 1 since you would never willingly round a capacity number *down*. A specialty engine could have 100 times the capacity of a CP, yet both would show a '1' for a sufficiently powerful CP. Alan Altmark z/VM Development IBM Endicott
